7x^2-14x-48=8

Solution for 7x^2-14x-48=8 equation:

7x^2-14x-48=8

We move all terms to the left:

7x^2-14x-48-(8)=0

We add all the numbers together, and all the variables

7x^2-14x-56=0

a = 7; b = -14; c = -56;
Δ = b2-4ac
Δ = -142-4·7·(-56)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-42}{2*7}=\frac{-28}{14}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+42}{2*7}=\frac{56}{14}
=4
$